Mathématiques

Question

Bonjour j’ai un DM à faire Pour demain quelqu'un pourrait m'aider svp

1. factoriser chacune des expressions suivante:

A(x) = 4(3x+1)²-36

B(x) = x²+4x+4-9(x²-4)

C(x) = (x²-9)-25(x²-6x+9)

D(x) = (4x²-49)+2x(2x+7)

Merci

1 Réponse

  • Bonsoir,

    A(x) = 4(3x+1)²-36
    A(x) = 2^2(3x + 1)^2 - 6^2
    A(x) = [2(3x + 1) - 6][2(3x + 1) + 6]
    A(x) = (6x + 2 - 6)(6x + 2 + 6)
    A(x) = (6x - 4)(6x + 8)
    A(x) = 4(3x - 2)(3x + 4)

    B(x) = x²+4x+4-9(x²-4)
    B(x) = (x + 2)^2 - 3^2(x - 2)(x + 2)
    B(x) = (x + 2)[x + 2 - 9(x - 2)]
    B(x) = (x + 2)(x + 2 - 9x + 18)
    B(x) = (x + 2)(-8x + 20)
    B(x) = 4(x + 2)(-2x + 5)

    C(x) = (x²-9)-25(x²-6x+9)
    C(x) = (x - 3)(x + 3) - 5^2(x - 3)^2
    C(x) = (x - 3)[x + 3 - 25(x - 3)]
    C(x) = (x - 3)(x + 3 - 25x + 75)
    C(x) = (x - 3)(-24x + 78)
    C(x) = 6(x - 3)(-4x + 13)

    D(x) = (4x²-49)+2x(2x+7)
    D(x) = (2x - 7)(2x + 7) + 2x(2x + 7)
    D(x) = (2x + 7)(2x - 7 + 2x)
    D(x) = (2x + 7)(4x - 7)

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