Factoriser les expressions suivantes car je ne comprends pas A(t)=(2t-1)(t+1)-2(t+1) B(t)=(t-4)²+(t-4)(2t+3) C(t)=(2t-1)(3t+5)+4t(3t+5) D(t)=(5t-1)(3t-2)
Mathématiques
corinnefr59
Question
Factoriser les expressions suivantes car je ne comprends pas A(t)=(2t-1)(t+1)-2(t+1) B(t)=(t-4)²+(t-4)(2t+3) C(t)=(2t-1)(3t+5)+4t(3t+5) D(t)=(5t-1)(3t-2)-(5t-1)² E(t)=(3t+1)²-(4t-1)² F(t)=9(t+1)²-4(2t+3)² G(t)=t²+2t+1+(t+1)(3t-5) H(t)=(2t+1)²+4t²-1 merci d'avance
1 Réponse
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1. Réponse loulakar
Bonsoir
Factoriser une expression veut dire trouver un facteur commun.
A(t)=(2t-1)(t+1)-2(t+1)
A(t) = (t + 1)(2t - 1 - 2)
A(t) = (t + 1)(2t - 3)
B(t)=(t-4)²+(t-4)(2t+3)
B(t) = (t - 4)(t - 4 + 2t + 3)
B(t) = (t - 4)(3t - 1)
C(t)=(2t-1)(3t+5)+4t(3t+5)
C(t) = (3t + 5)(2t - 1 + 4t)
C(t) = (3t + 5)(6t - 1)
D(t)=(5t-1)(3t-2)-(5t-1)²
D(t) = (5t - 1)(3t - 2 - 5t + 1)
D(t) = (5t - 1)(-2t - 1)
E(t)=(3t+1)²-(4t-1)²
E(t) = a^2 - b^2
E(t) = (a - b)(a + b)
E(t) = (3t + 1 - 4t + 1)(3t + 1 + 4t - 1)
A toi de finir...
F(t)=9(t+1)²-4(2t+3)²
F(t) = 3²(t+ 1)² - 2²(2t + 3)²
F(t) = [3(t + 1) - 2(2t + 3)][3(t + 1) + 2(2t + 3)]
F(t) = (3t + 3 - 4t - 6)(3t + 3 + 4t + 6)
Tu finis....
G(t)=t²+2t+1+(t+1)(3t-5)
G(t) = (t)² + 2 * t * 1 + (1)² + (t + 1)(3t - 5)
G(t) = a^2 + 2ab + b^2 + ....
G(t) = (a + b)^2 + ....
G(t) = (t + 1)² + (t + 1)(3t - 5)
G(t) = (t + 1)(t + 1 + 3t - 5)
Je te laisse finir....
H(t)=(2t+1)²+4t²-1
H(t) = (2t + 1)² + (2t)² - 1²
H(t) = (2t + 1)² + a² - b²
H(t) = (2t + 1)² + (a - b)(a + b)
H(t) = (2t + 1)² + (2t - 1)(2t + 1)
H(t) = (2t + 1)(2t + 1 + 2t - 1)
Tu finis....